1836 United States presidential election in Alabama

1836 United States presidential election in Alabama

← 1832 November 3 – December 7, 1836 1840 →

Nominee Martin Van Buren Hugh White Party Democratic Whig Home state New York Tennessee Running mate Richard Johnson John Tyler Electoral vote 7 0 Popular vote 20,638 16,658 Percentage 55.34% 44.66%

County results Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% White   50–60%   60–70%   70–80%   80–90% Unknown/No Vote

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

Elections in Alabama
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Ballot measures 2000 Amendment 2 2006 Amendment 774 2020 Amendment 1
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Mobile Mayoral elections 2021
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The 1836 United States presidential election in Alabama took place between November 3 and December 7, 1836, as part of the 1836 presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Alabama by a margin of 10.68%.

• United States presidential elections in Alabama

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