how to create the script required for the systemd service

Question

hey i'm trying to get my system to run a terminal command on startup everything i've found says to launch a script using a systemd service but nothing even begins to go into what i'd even type in that script and I'm not a programmer. the command i want to run is rclone sync / b2-004:alice-ubtntu-2295 --copy-links

I use Ubuntu 22.04

Answer 1

Here is a simple means to get it done, but please look at man systemd systemd.service to learn a bit more:

1. Create the systemd unit file with your nano text editor:

   sudo nano /etc/systemd/system/my-clone-sync.service
   

2. Add the following lines:

   [Unit]
   Description=Clone Sync Service
   
   [Service]
   Type=oneshot
   ExecStart=/usr/bin/clone sync / b2-004:alice-ubtntu-2295 --copy-links
   RemainAfterExit=yes
   
   [Install]
   WantedBy=multi-user.target
   

   Make sure to provide the full path to the clone command if it's not in the system's default PATH.

3. Save and exit:

   Save the changes to the systemd unit file and exit the text editor.

   • ctrl + X
   • shift + Y
   • Return key

4. Enable and start the service:

   After modifying the unit file, enable and start the service as previously described:

   sudo systemctl enable my-clone-sync.service
   sudo systemctl start my-clone-sync.service
   

5. Check the service status:

   To verify that the service is running and monitor its status:

   sudo systemctl status my-clone-sync.service